INEQUALITY'S BLOG

July 26, 2010

(Van Khea):Problem 004

Filed under: the new math — KKKVVV @ 3:42 pm

Let a, b, c,p,q,r>0. Prove that:

\displaystyle \frac{4}{(p+q)(a+b)^{2}}+\frac{4}{(q+r)(b+c)^{2}}+\frac{4}{(r+p)(c+a)^{2}}\displaystyle \leq \frac{1}{pa^{2}}+\frac{1}{qb^{2}}+\frac{1}{rc^{2}}

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