INEQUALITY'S BLOG

July 29, 2010

(van khea):Problem 020

Filed under: Uncategorized — KKKVVV @ 12:57 am

Let a, b, c>0 ; a+b+c=1. Prove that:

5(\sqrt{a}+\sqrt{b}+\sqrt{c})\geq \sqrt{ab+bc+ca}+24\sqrt[3]{abc}

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