INEQUALITY'S BLOG

July 29, 2010

(van khea):Problem 021

Filed under: Uncategorized — KKKVVV @ 1:03 am

Let a, b, c>k\geq 2. Prove that:

\displaystyle \frac{1}{\sqrt[3]{a-k}}+\frac{1}{\sqrt[3]{b-k}}+\frac{1}{\sqrt[3]{c-k}}+\sqrt[3]{abc}\geq k+4

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