INEQUALITY'S BLOG

August 1, 2010

Problem 029

Filed under: Uncategorized — KKKVVV @ 12:13 am

Let a, b, c be positive real numbers satisfying a\geq b\geq c and abc=1. Prove that:

\displaystyle \frac{1}{a^2(b+c)}+\frac{1}{b^2(c+a)}+\frac{1}{c^2(a+b)}\geq \frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}

 

Van khea     

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