INEQUALITY'S BLOG

August 1, 2010

Problem 028

Filed under: Uncategorized — KKKVVV @ 12:06 am

Let a\geq b\geq c>0. Prove that:

\displaystyle \frac{a^2b^2}{b+c}+\frac{b^2c^2}{c+a}+\frac{c^2a^2}{a+b}\geq abc\biggl(\frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}\biggl)

 

Van Khea

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