INEQUALITY'S BLOG

November 5, 2010

Problem 57 (Van Khea)

Filed under: the new math — KKKVVV @ 7:32 pm

Let a, b, c>0 ; a+b+c=3. Prove that:

\displaystyle \frac{a^{\frac{2}{3}}}{b\sqrt{b+2c}}+\frac{b^{\frac{2}{3}}}{c\sqrt{c+2a}}+\frac{c^{\frac{2}{3}}}{a\sqrt{a+2b}}\geq \sqrt{3}

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