INEQUALITY'S BLOG

November 21, 2010

Problem 60: van khea

Filed under: Uncategorized — KKKVVV @ 6:16 am

Let a, b, c>0 ; x, y, z\in [0, 1] .Prove that:
\displaystyle a^2\sqrt{2+x+y}+b^2\sqrt{2+y+z}+c^2\sqrt{2+z+x}\geq \frac{\sqrt{2}}{3}(a+b+c)^2\sqrt{1+\sqrt[3]{xyz}}

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