INEQUALITY'S BLOG

November 22, 2010

Problem 62: van khea

Filed under: Uncategorized — KKKVVV @ 12:48 am

Let a, b, c>0 ; abc=1 . Prove that
\displaystyle \frac{a^3\sqrt{2a+b}}{(a+b)^2}+\frac{b^3\sqrt{2b+c}}{(b+c)^2}+\frac{c^3\sqrt{2c+a}}{(c+a)^2}\geq \frac{3\sqrt{3}}{4}

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