INEQUALITY'S BLOG

November 22, 2010

Problem 63: van khea

Filed under: Uncategorized — KKKVVV @ 1:00 am

7) Let a, b, c>0 ដែល abc=1. Prove that:
\displaystyle P=\frac{a^4\sqrt[3]{5a+7b}}{\sqrt{a+b}}+\frac{b^4\sqrt[3]{5b+7c}}{\sqrt{b+c}}+\frac{c^4\sqrt[3]{5c+7a}}{\sqrt{c+a}}\geq 3\sqrt[3]{3}.\sqrt[6]{2}

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