INEQUALITY'S BLOG

November 22, 2010

Problem 67: van khea

Filed under: Uncategorized — KKKVVV @ 1:08 am

Let a, b, c>0 ; abc=8. Prove that
\displaystyle \frac{\sqrt[3]{7a+5b}}{c^4(2b+3c)}+\frac{\sqrt[3]{7b+5c}}{a^4(2c+3a)}+\frac{\sqrt[3]{7c+5a}}{b^4(2a+3b)}\geq \frac{3\sqrt[3]{3}}{40}

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