INEQUALITY'S BLOG

November 26, 2010

Problem 72: van khea

Filed under: the new math — KKKVVV @ 8:52 am

Let a, b, c be positive real numbers such that a\geq b\geq c and abc=1. Prove that:
\displaystyle \frac{a}{\sqrt{a+b}}+\frac{b}{\sqrt{b+c}}+\frac{c}{\sqrt{c+a}}\geq \frac{3}{\sqrt{2}}

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