INEQUALITY'S BLOG

December 16, 2010

Problem 73: van khea

Filed under: Uncategorized — KKKVVV @ 10:31 am

Let a, b, c>0. Prove that \displaystyle \biggl(\frac{a}{a+b}+\frac{b}{b+c}+\frac{c}{c+a}\biggl)\biggl(a^2+b^2+c^2-\frac{3abc}{a+b+c}\biggl)\geq ab+bc+ca

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