INEQUALITY'S BLOG

December 16, 2010

Problem 74: van khea

Filed under: Uncategorized — KKKVVV @ 10:35 am

Let a, b, c>0. Prove that:  \displaystyle \frac{ab}{\sqrt{c+a}}+\frac{bc}{\sqrt{a+b}}+\frac{ca}{\sqrt{b+c}}\leq \frac{\sqrt{2}}{\sqrt{3}}(a+b+c)^{\frac{3}{2}}-\frac{3}{\sqrt{2}}\sqrt{abc}

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