INEQUALITY'S BLOG

July 11, 2011

Problem 225 (van khea)

Filed under: Problem by Van Khea — KKKVVV @ 11:24 pm

a, b, c>0\& abc=1. Prove that: \displaystyle \frac{a^3}{b^2+c^3}+\frac{b^3}{c^2+a^3}+\frac{c^3}{a^2+b^3}\geq \frac{3}{2}

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