INEQUALITY'S BLOG

July 11, 2011

Problem 228 (van khea)

Filed under: Problem by Van Khea — KKKVVV @ 11:39 pm

Let a, b, c>0\& a^2+b^2+c^2=3. Prove that: \displaystyle \frac{a^2}{1+b^3}+\frac{b^2}{1+c^3}+\frac{c^2}{1+a^3}\geq \frac{3}{2}

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