INEQUALITY'S BLOG

July 11, 2011

Problem 229 (van khea)

Filed under: Problem by Van Khea — KKKVVV @ 11:46 pm

Prove that for any positive real numbers $a, b, c$ we have: $\displaystyle \frac{1}{a^3(b^3+abc)}+\frac{1}{b^3(c^3+abc)}+\frac{1}{c^3(a^3+abc)}\geq \frac{3}{2a^2b^2c^2}$