INEQUALITY'S BLOG

August 13, 2011

Problem 275 Van Khea

Filed under: Problem by Van Khea — KKKVVV @ 9:59 am

Let a, b, c be positive real numbers such that a^2+b^2+c^2=1. Prove that

\displaystyle \frac{1}{a}+\frac{1}{b}+\frac{1}{c}\geq 6\sqrt[3]{abc}+\frac{1}{3abc}

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