INEQUALITY'S BLOG

August 13, 2011

Problem 276 Van Khea

Filed under: Problem by Van Khea — KKKVVV @ 10:02 am

Let a, b, c be positive real numbers such that a^2+b^2+c^2=1. Prove that

\displaystyle a+b+c-4abc\geq \frac{5}{3\sqrt{3}}

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