INEQUALITY'S BLOG

August 13, 2011

Problem 276 Van Khea

Filed under: Problem by Van Khea — KKKVVV @ 10:02 am

Let $a, b, c$ be positive real numbers such that $a^2+b^2+c^2=1$. Prove that

$\displaystyle a+b+c-4abc\geq \frac{5}{3\sqrt{3}}$