INEQUALITY'S BLOG

October 17, 2012

Last two digit (vankhea formula)

Filed under: the new math — KKKVVV @ 11:25 am

If p\equiv r(mod 20); r\in \mathbb{N}^{*}; 1\leq r\leq 20 and \forall{x, y\in \mathbb{N}}; 0\leq x\leq 9; 0\leq y\leq 9. Then we get:
(\overline{xy})^p\equiv y^p+10x(y^r)'(mod 100) with (y^r)'=ry^{r-1}

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Last one digit (vankhea formula )

Filed under: the new math — KKKVVV @ 11:18 am

If p\equiv r(mod 4) ; r\in \mathbb{N}^{*} ; 1\leq r\leq 4 and \forall{x\in \mathbb{N}} ; 0\leq x\leq 9 we get:
x^p\equiv x^r(mod 10)