Last one digit (vankhea formula )

October 17, 2012

Filed under: the new math — KKKVVV @ 11:18 am

If $p\equiv r(mod 4) ; r\in \mathbb{N}^{*} ; 1\leq r\leq 4$ and $\forall{x\in \mathbb{N}} ; 0\leq x\leq 9$ we get:
$x^p\equiv x^r(mod 10)$

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